Closed Bug 100728 Opened 23 years ago Closed 23 years ago

View source displays the original page of frameset, not the current page

Categories

(SeaMonkey :: General, defect)

x86
Windows ME
defect
Not set
blocker

Tracking

(Not tracked)

VERIFIED DUPLICATE of bug 55583

People

(Reporter: jrhett, Assigned: asa)

Details

From Bugzilla Helper: User-Agent: Mozilla/5.0 (Windows; U; Win 9x 4.90; en-US; rv:0.9.4) Gecko/20010913 BuildID: 2001091303 If you make a 2part frameset. Then have one submit to the other. When you do a "View Source" on the second frameset, it shows the source from the original frameset invocation, not the currently displayed data. Reproducible: Always Steps to Reproduce: 1. Make a small CGI 'echo' that prints out a single input field. 2. Make a frameset with "frame1" and "frame2" frames. 3. Put a form in frame1 that submits "die die die" to 'echo', target frame2. 4. Put a static "hello world" page inside frame2. 5. Load the page, view source on frame2 --> "Hello world". 6. Submit the form from frame1. 7. Witness that frame2 now says "die die die". 8. View source on frame2 --> "Hello world". Actual Results: The view source screen displayed the original static content for the frame. Expected Results: View source should display the source of the page actually visible inside the frame.
Yep. That's because view source referches from the server. This should be fixed as soon as we have an API in place to pull from cache instead. *** This bug has been marked as a duplicate of 55583 ***
Status: UNCONFIRMED → RESOLVED
Closed: 23 years ago
Resolution: --- → DUPLICATE
Boris for our holiday gift this year will you fix this problem soon? ;-) verf dupe.
Status: RESOLVED → VERIFIED
URL: any
Product: Browser → Seamonkey
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