Closed
Bug 100728
Opened 23 years ago
Closed 23 years ago
View source displays the original page of frameset, not the current page
Categories
(SeaMonkey :: General, defect)
Tracking
(Not tracked)
People
(Reporter: jrhett, Assigned: asa)
Details
From Bugzilla Helper:
User-Agent: Mozilla/5.0 (Windows; U; Win 9x 4.90; en-US; rv:0.9.4) Gecko/20010913
BuildID: 2001091303
If you make a 2part frameset. Then have one submit to the other. When you do a
"View Source" on the second frameset, it shows the source from the original
frameset invocation, not the currently displayed data.
Reproducible: Always
Steps to Reproduce:
1. Make a small CGI 'echo' that prints out a single input field.
2. Make a frameset with "frame1" and "frame2" frames.
3. Put a form in frame1 that submits "die die die" to 'echo', target frame2.
4. Put a static "hello world" page inside frame2.
5. Load the page, view source on frame2 --> "Hello world".
6. Submit the form from frame1.
7. Witness that frame2 now says "die die die".
8. View source on frame2 --> "Hello world".
Actual Results: The view source screen displayed the original static content
for the frame.
Expected Results: View source should display the source of the page actually
visible inside the frame.
Comment 1•23 years ago
|
||
Yep. That's because view source referches from the server. This should be
fixed as soon as we have an API in place to pull from cache instead.
*** This bug has been marked as a duplicate of 55583 ***
Status: UNCONFIRMED → RESOLVED
Closed: 23 years ago
Resolution: --- → DUPLICATE
Comment 2•23 years ago
|
||
Boris for our holiday gift this year will you fix this problem soon? ;-)
verf dupe.
Status: RESOLVED → VERIFIED
Updated•20 years ago
|
Product: Browser → Seamonkey
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Description
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